Description

   Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given n numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given n numbers finds one that is different in evenness.

Input

  The first line contains integer n (3 ≤ n ≤ 100) — amount of numbers in the task. The second line contains n space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.

Output

  Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.

Sample Input

Input
5
2 4 7 8 10
Output
3
Input
4
1 2 1 1
Output
2

///题意：本题题意很简单，就是给一些数，要你找出这些数种那一个奇偶性不相同的唯一数的位置。
//@zhangxiaoyu
//2015/8/12

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
using namespace std;

int a[105];
int main()
{
    int tt;
    while(~scanf("%d",&tt))
    {
        int ans1=0,ans2=0;
        int pos1,pos2;
        for(int i=1;i<=tt;i++)
        {
            scanf("%d",&a[i]);
            if(a[i]%2==0)
            {
                ans1++;
                pos1=i;
            }
            else
            {
                ans2++;
                pos2=i;
            }
        }
        if(ans1>ans2) ///偶数比ji数多
        {
            printf("%d\n",pos2);
        }
        else
        {
            printf("%d\n",pos1);
        }
    }
    return 0;
}