由于A,B,P很大,所以要用快速幂和快速乘来计算。
注意java选手千万不要用StreamTokenizer输入,要用Scanner,用StreamTokenizer你会一直wa过不了!!!!
import java.math.*;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.io.StreamTokenizer;
import java.util.*;
public class Main {
public static long num[] = new long[1023];
public static int k=0;
public static void main(String args[])throws IOException
{
StreamTokenizer in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));
PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out));
Scanner sc = new Scanner(System.in);
int T = sc.nextInt();
while(T -- > 0) {
long a = sc.nextLong();
long b = sc.nextLong();
long mod = sc.nextLong();
System.out.println(pow(a , b , mod) % mod);
}
}
public static long pow(long A,long B,long P)
{
long temp=1;
while(B>0)
{
if((B&1)==1)
{
temp=cheng(temp,A,P);
}
A= cheng(A,A,P);
B>>=1;
}
return temp;
}
public static long cheng(long a, long b,long P)
{
long ans = 0;
while (b > 0)
{
if ((b & 1) != 0)
{
ans =(ans+ a)%P;
}
b >>= 1;
a = (a+a)%P;
}
return ans;
}
}

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