Problem Description

Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone s .

 

 

Input

There are multiple test cases. The first line of input contains an integer T (1≤T≤106 ), indicating the number of test cases. For each test case:
The first line contains two integers a , b (0≤a≤23,0≤b≤59 ) and a string s in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤9 ).

 

Output

 

For each test, output the time in the format of hh:mm (24-hour clock).

 

 

 

Sample Input

 

3 11 11 UTC+8 11 12 UTC+9 11 23 UTC+0

 

 

Sample Output

 

11:11 12:12 03:23

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=6308

题意：北京标准时间是UTC+8，现在给出标准的北京时间和别的地方的时区，要求别的地方的当前时间

AC代码

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main()
{
    int a,b,c,d,e,s,w;
    char m[20];
    while(~scanf("%d",&a))
    {
        while(a--)
        {
            s=0;w=0;
            scanf("%d %d %s",&b,&c,&m);
            d=strlen(m);
            if(d==5)
            {
                s=m[4]-'0';
            }
            else if(d==6)
            {
                s=(m[4]-'0')*10+m[5]-'0';
            }
            else if(d==7)
            {
                s=m[4]-'0';
                w=m[6]-'0';
            }
            else if(d==8)
            {
                s=(m[4]-'0')*10+m[5]-'0';
                w=m[7]-'0';
            }
            if(m[3]=='-')
            {
                b=b-8-s;
                e=w*6;
                if(e<=c)
                    c=c-e;
                else
                {
                    b--;
                    c=60+c-e;
                }
            }
            else
            {
                b=b-(8-s);
                e=w*6;
                if(e+c<60)
                    c=c+e;
                else
                {
                    b++;
                    c=c+e-60;
                }
            }
            if(b>=24)
                b=b-24;
            else if(b<0)
                b=b+24;
            printf("%02d:%02d\n",b,c);
        }
    }
    return 0;
}