题解 | 删除有序链表中重复的元素-II

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 
# @return ListNode类
#
class Solution:
    def deleteDuplicates(self , head: ListNode) -> ListNode:
        # write code here
        if head == None:
            return head
        cur = head
        pre = ListNode(-1)
        pre_head = pre
        nums = []
        while cur:
            nums.append(cur.val)
            cur = cur.next
        nums2 = []
        for i in nums:
            if nums.count(i) == 1:
                nums2.append(i)
            else:
                continue
        for i in nums2:
            t = ListNode(i)
            pre.next = t
            pre = pre.next
        return pre_head.next