#思路：
#遍历一遍，判断字符并计数
# str1=input()
# a=b=c=d=0
# for i in str1:
#     if i.isalpha():
#         a+=1
#     elif i==" ":
#         b+=1
#     elif i.isdigit():
#         c+=1
#     else:
#         d+=1
# print(a)
# print(b)
# print(c)
# print(d)

#正则表达式解法
import re
s=input()
n1=len(re.findall(r"[a-zA-Z]",s))
n2=len(re.findall(r" ",s))
n3=len(re.findall(r"[0-9]",s))
n4=len(s)-n1-n2-n3
print(n1)
print(n2)
print(n3)
print(n4)