1.通配符匹配
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/wildcard-matching
思路:动态规划
class Solution { public: bool isMatch(string s, string p) { int m = s.size(); int n = p.size(); vector<vector<int>> dp(m + 1, vector<int>(n + 1)); dp[0][0] = true; for (int i = 1; i <= n; ++i) { if (p[i - 1] == '*') { dp[0][i] = true; } else { break; } } for (int i = 1; i <= m; ++i) { for (int j = 1; j <= n; ++j) { if (p[j - 1] == '*') { dp[i][j] = dp[i][j - 1] | dp[i - 1][j]; } else if (p[j - 1] == '?' || s[i - 1] == p[j - 1]) { dp[i][j] = dp[i - 1][j - 1]; } } } return dp[m][n]; } };