题解 | #数字颠倒#

#include <stdio.h>

int main() {
    int a = 0,i = 0;

    scanf("%d",&a);
    if(a == 0)
    {
        printf("%d",a);
    }
    int arr[32] = {0};
    while(a!=0)
    {
        arr[i++] = a%10;
        a /= 10;
    }
    for(int j = 0;j<i;j++)
    {
        printf("%d",arr[j]);
    }
    return 0;
}