Lady Layton with Math
/*
Author : lifehappy
*/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 2e6 + 10, mod = 1e9 + 7;
int prime[N], cnt, n;
ll phi[N];
bool st[N];
void init() {
phi[1] = 1;
for(int i = 2; i < N; i++) {
if(!st[i]) {
prime[++cnt] = i;
phi[i] = i - 1;
}
for(int j = 1; j <= cnt && 1ll * i * prime[j] < N; j++) {
st[i * prime[j]] = 1;
if(i % prime[j] == 0) {
phi[i * prime[j]] = phi[i] * prime[j];
break;
}
phi[i * prime[j]] = phi[i] * (prime[j] - 1);
}
}
for(int i = 1; i < N; i++) {
phi[i] = (phi[i] + phi[i - 1]) % mod;
}
}
unordered_map<int, ll> ans_s;
ll Djs(int n) {
if(n < N) return phi[n];
if(ans_s.count(n)) return ans_s[n];
ll ans = 1ll * n * (n + 1) / 2 % mod;
for(int l = 2, r; l <= n; l = r + 1) {
r = n / (n / l);
ans = (ans - (r - l + 1) * Djs(n / l) % mod + mod) % mod;
}
return ans_s[n] = ans;
}
int main() {
// freopen("in.txt", "r", stdin);
// freopen("out.txt", "w", stdout);
// ios::sync_with_stdio(false), cin.tie(0), cout.tie(0);
int T;
init();
scanf("%d", &T);
while(T--) {
ll ans = 0;
scanf("%d", &n);
for(int l = 1, r; l <= n; l = r + 1) {
r = n / (n / l);
ans = (ans + 1ll * (Djs(r) - Djs(l - 1)) * (2ll * Djs(n / l) - 1) % mod + mod) % mod;
}
printf("%lld\n", ans);
}
return 0;
} 
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