题解 | #数位五五#

//BC151 数位五五 
#include<stdio.h>
int main()
{
	int a = 0;
	int b = 0; 
	int sum = 0;
	int count = 0; 
	int n = 0;
	scanf("%d %d", &a, &b); 
	for (int i = a; i <= b; i++)
	{
		//把i给一个变量，不能直接用i，会把i的值改变
		n = i; 
		while (n) 
		{
			//求出每一位
			sum += n % 10;   
			n /= 10; 
		}
		if (sum % 5 == 0)
			count++; 
		sum = 0; 
	}
	printf("%d\n", count); 
	return 0; 
}