题解 | #球的半径和体积#

python 写法，没法用 numpy，自己赋值一个 PI

import sys
import math

PI = 3.141592653589793

for line in sys.stdin:
    a = line.split()
    x0 = eval(a[0])
    y0 = eval(a[1])
    z0 = eval(a[2])
    x1 = eval(a[3])
    y1 = eval(a[4])
    z1 = eval(a[5])
    r = math.sqrt((x1-x0)**2 + (y1-y0)**2 + (z1-z0)**2)

    print(format(r, '.3f') + ' ' + format(4/3*PI*r*r*r, '.3f'))