题解 | #统计成绩#

#include <malloc.h>
#include <stdio.h>
int main() {
    int n;
    scanf("%d", &n);
    double* p = (double*)malloc(n * sizeof(double));
    int i;
    double max, min, average, sum;
    max = 0.0, min = 0.0, average = 0.0;
    sum = 0;
    for (i = 0; i < n; i++) {
        scanf("%lf", p + i);
        sum += *(p + i);
    }
    max = min = p[0];
    for (i = 0; i < n; i++) {
        if (*(p + i) > max) {
            max = *(p + i);
        }
        if (*(p + i) < min) {
            min = *(p + i);
        }
    }
    average = sum / n;
    printf("%.2lf %.2lf %.2lf", max, min, average);
    free(p);
    return 0;
}