solution：这个题目大意是求一个数的阶乘的位数，咱们很容易想到一个数的位数为(int)log10(n) + 1,故数n的阶乘的位数为(int)log10(1 * 2 * 3 * … * n) + 1

#include <bits/stdc++.h>
using namespace std;

int main()
{
	int t, n;
	cin >> t;
	while (t--)
	{
		cin >> n;
		double s = 0;
		for (int i = 1; i <= n; ++i)s += log10(i);
		cout << int(s) + 1 << endl;
	}
	return 0;
}