题解 | 统计字符串中各类型字符的个数

#include <iostream>
#include <cstring>
using namespace std;

int main() {

    int letter = 0;
    int digit = 0;
    int space = 0;
    int other = 0;
    
    char buf[1024] = {0};
    cin.getline(buf, sizeof(buf));

    // write your code here......
    for(int i=0; buf[i]!='\0'; i++){
        if(buf[i]==' '){
            space++;
        }else if (buf[i]>='0' && buf[i]<='9') {
            digit++;
        }else if ((buf[i]>='A' && buf[i]<='Z')||(buf[i]>='a' && buf[i]<='z')) {
            letter++;
        }else{
            other++;
        }
    }
    

    cout << "letter:" << letter << " digit:" << digit << " space:" << space << " other:" << other << endl;

    return 0;
}