select
customer_id
,customer_name
,latest_order
from
(
select
o.customer_id customer_id
,customer_name
,product_name latest_order
,rank()over(partition by customer_id order by order_date desc) rk
from orders o
join customers c
on o.customer_id = c.customer_id
join products p
on o.product_id = p.product_id
) t
where rk = 1
order by customer_id

京公网安备 11010502036488号