题解 | #删除链表的节点#

import java.util.*;

/*
 * public class ListNode {
 *   int val;
 *   ListNode next = null;
 *   public ListNode(int val) {
 *     this.val = val;
 *   }
 * }
 */

public class Solution {
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     *
     * @param head ListNode类
     * @param val int整型
     * @return ListNode类
     */
    public ListNode deleteNode (ListNode head, int val) {
        // write code here
        //添加一个头节点
        ListNode dummyHead = new ListNode(-1);
        dummyHead.next = head;
        //前序节点
        ListNode pre = dummyHead;
        //当前节点
        ListNode cur = pre.next;

        while (cur != null) {
            if (cur.val == val) {
                pre.next = cur.next;
                break;
            }
            pre = cur;
            cur = cur.next;
        }
        head = dummyHead.next;
        dummyHead = null;
        return head;
    }
}