题解 | #简单密码#

import java.util.*;

public class Main{
    //定义map容器存储按键对应数字字符的容器
    private static Map<String,String> map = new HashMap<>();
    //静态初始化、加载map容器
    static{
        map.put("1","1");
        map.put("abc","2");
        map.put("def","3");
        map.put("ghi","4");
        map.put("jkl","5");
        map.put("mno","6");
        map.put("pqrs","7");
        map.put("tuv","8");
        map.put("wxyz","9");
        map.put("0","0");
    }
    
    public static void main(String[] args){
       Scanner scanner = new Scanner(System.in);
       while(scanner.hasNext()){
           String str = scanner.nextLine();
           char[] chars = str.toCharArray();
           //构造buffer容器存储转换后的字符串
           StringBuffer buffer = new StringBuffer();
           for(char c : chars){
               //如果是正整数则不需要进行加密
               if(c>='0'&& c<='9'){
                    buffer.append(String.valueOf(c));
                }else if(c>='A'&& c<='Y'){ //如果是A~Y的大写字母则需要将其+32位转换成小写再向后移1位
                    char newChar = (char)(c+32+1);
                    buffer.append(String.valueOf(newChar));
                }else if(c=='Z'){ //如果是Z则加密成a
                    buffer.append("a");
                }else{
                //去除map容器中的key与字符进行校验并加密
                Set<String> keys = map.keySet();
                for(String k : keys){
                    if(k.contains(String.valueOf(c)))
                        buffer.append(map.get(k));
                }
               }
           }
           System.out.print(buffer.toString());
       }
    }
}