题解 | #查找输入整数二进制中1的个数#

方法1： python

while True:
    try:
         a = int(input())
         num = 0
         while a:
             if a & 0x0001:
                 num+=1
             a = a >>1
         print(num)

    except:
        break

方法2：python

while True:
    try:
        print(bin(int(input())).count('1'))
    except:
        break