题解 | #数字反转#

#include<stdio.h>
int reverse(int n){
	int m=0;
	while (n != 0){
		m = m * 10 + n % 10;
		n = n / 10;
	}
	return m;
}
int main(){
	int a, b;
	while (scanf("%d %d", &a, &b) != EOF){
		if (reverse(a + b) == reverse(a) + reverse(b)){
			printf("%d\n", a + b);
		}
		else{
			printf("NO\n");
		}
	}
}