题解 | 时间转换

#include <stdio.h>

int main() {
    int hour = 0;
    int min = 0;
    int s = 0;
    scanf("%d",&s);
    if(s==0)
    {
        printf("%d %d %d",0,0,0);
    }
    else if(s>0)
    {
    hour =s/3600;
    s= s % 3600;
    min=s / 60;
    s = s % 60;
    printf("%d %d %d",hour,min,s);
    }
    return 0;
}

画一个流程图，一目了然，要注意0秒的特殊状态