题解 | #输出单向链表中倒数第k个结点#

while True:
    try:
        n = int(input())
        val = input().split()
        k = int(input())
        for i in range(len(val)):
            if i == len(val) - k and (k != 0):
                print(val[i])
            if k == 0:
                print(0)
    except:
        break