1065 A+B and C (64bit) (20 分)
Given three integers A, B and C in [−263,263], you are supposed to tell whether A+B>C.
Input Specification:
The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line Case #X: true
if A+B>C, or Case #X: false
otherwise, where X is the case number (starting from 1).
Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false
不看书都没注意到 题目取值范围2的63次方是闭区间...不看书都没注意到原来题目也没考虑到这一点...
作者简直不要太细心 好评!
代码是书上的,回头得好好学一下组成原理了...
#include<cstdio>
int main()
{
int T,tcase=1;
scanf("%d",&T);
while(T--)
{
long long a,b,c;
scanf("%lld%lld%lld",&a,&b,&c);
long long res=a+b;
bool flag;
if(a>0&&b>0&&res<0) flag=true;
else if(a<0&&b<0&&res>=0) flag=false;
else if(res>c) flag=true;
else flag=false;
if(flag==true){
printf("Case #%d: true\n",tcase++);
}else{
printf("Case #%d: false\n",tcase++);
}
}
return 0;
}