题解 | 计算字符串的编辑距离

import sys

s = sys.stdin.readline().strip()
t = sys.stdin.readline().strip()

# 长度
m = len(s)
n = len(t)

# 初始化
dp = [ [0] * (n + 1) for _ in range(m + 1) ]

for i in range(m + 1):
    for j in range(n + 1):
        if i == 0:
            dp[0][j] = j
            continue
        if j == 0 :
            dp[i][0] = i
            continue
        if s[i - 1] != t[j - 1]: 
            dp[i][j] = min(dp[i - 1][j], dp[i][j - 1], dp[i - 1][j - 1]) + 1
        else:
            dp[i][j] = dp[i - 1][j - 1]

print(dp[m][n])