题解 | #数值的整数次方#

public class Solution {
    public double Power(double base, int exponent) {
        if(exponent > 1 || exponent < -1) {
            int a = (int)(exponent / 2);
            double res = Power(base, a);
            return res * res * Power(base, exponent - a * 2);
        } else if(exponent == 0) {
            return 1.0;
        } else if(exponent == 1) {
            return base;
        } else {
            return 1.0 / base;
        }
    }
}