A 牛牛爱字符串
题目地址:
基本思路:
根据题意模拟就行了,
但是要注意首先是输入有空格要用,
然后是数字可能很大,要用字符串方式储存,还有就是注意前导零,
细节还是挺多的,但是整体难度不大。
参考代码:
#pragma GCC optimize(2) #pragma GCC optimize(3) #include <bits/stdc++.h> using namespace std; #define IO std::ios::sync_with_stdio(false); cin.tie(0) #define int long long #define SZ(x) ((int)(x).size()) #define all(x) (x).begin(), (x).end() #define rep(i, l, r) for (int i = l; i <= r; i++) #define per(i, l, r) for (int i = l; i >= r; i--) #define mset(s, _) memset(s, _, sizeof(s)) #define pb push_back #define pii pair <int, int> #define mp(a, b) make_pair(a, b) #define INF 0x3f3f3f3f inline int read() { int x = 0, neg = 1; char op = getchar(); while (!isdigit(op)) { if (op == '-') neg = -1; op = getchar(); } while (isdigit(op)) { x = 10 * x + op - '0'; op = getchar(); } return neg * x; } inline void print(int x) { if (x < 0) { putchar('-'); x = -x; } if (x >= 10) print(x / 10); putchar(x % 10 + '0'); } const int maxn = 1e5 + 10; char s[maxn]; signed main() { while (gets(s)) { int n = strlen(s); string ans; for (int i = 0; i < n; i++) { if (isdigit(s[i])) { bool v = false; while (i < n && isdigit(s[i])) { if (!v && s[i] == '0') { i++; continue; } v = true; ans += s[i]; i++; } if (!v) cout << 0 << ' '; else cout << ans << ' '; i--; ans = ""; } } cout << '\n'; } return 0; }