//抄的牛客上另外一个大佬的代码,结尾部分做了一丢丢修改
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
* 返回表达式的值
* @param s string字符串 待计算的表达式
* @return int整型
*/
int solve(string s) {
// write code here
int stack1[100],top1=-1,top2=-1;
char stack2[100];
int sum=0;
for(int i=0;i<s.size();i++)
{
if(s[i]>='0'&&s[i]<='9')
sum=sum*10+s[i]-'0';
else{
if(sum!=0)
{
stack1[++top1]=sum;
sum=0;
}
if(top2==-1||judge(s[i],stack2[top2])==true)
stack2[++top2]=s[i];
else{
if(s[i]==')')
{
while(stack2[top2]!='(')
{
char ch=stack2[top2--];
int x=stack1[top1--];
int y=stack1[top1--];
if(ch=='+')
stack1[++top1]=x+y;
else if(ch=='-')
stack1[++top1]=y-x;
else if(ch=='*')
stack1[++top1]=x*y;
else stack1[++top1]=y/x;
}
top2--;
}
else{
while(top2!=-1&&judge(s[i],stack2[top2])==false)
{
char ch=stack2[top2--];
int x=stack1[top1--];
int y=stack1[top1--];
if(ch=='+')
stack1[++top1]=x+y;
else if(ch=='-')
stack1[++top1]=y-x;
else if(ch=='*')
stack1[++top1]=x*y;
else stack1[++top1]=y/x;
}
stack2[++top2]=s[i];
}
}
}
}
if(sum!=0)
stack1[++top1]=sum;
while(top2!=-1)
{
char ch=stack2[top2--];
int x=stack1[top1--];
int y=stack1[top1--];
if (ch=='+') stack1[++top1]=x+y;
else if(ch=='-') stack1[++top1]=y-x;
else if(ch=='*') stack1[++top1]=x*y;
else stack1[++top1]=y/x;
}
return stack1[top1];
}
bool judge(char c1,char c2)
{
if(c1=='(')
return true;
else if(c1==')')
return false;
else if(c2=='(')
return true;
else if((c1=='*'||c1=='/')&&(c2=='+'||c2=='-'))
return true;
else return false;
}
};