这题要求我们构造数独,我的想法是让普通值都为k/n,每一行都安排一个特殊值k-k/n*(n-1),这个特殊值要求每一列都有,所以我把它安排在主对角线上,代码如下
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scanner=new Scanner(System.in);
int n=scanner.nextInt();
int k=scanner.nextInt();
int a[][]=new int[n][n];
for (int i = 0; i < a.length; i++) {
for (int j = 0; j < a.length; j++) {
if(j==i) {
a[i][j]=k-k/n*(n-1);
}else {
a[i][j]=k/n;
}
System.out.print(a[i][j]+" ");
}
System.out.println();
}
}
}



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