这题要求我们构造数独,我的想法是让普通值都为k/n,每一行都安排一个特殊值k-k/n*(n-1),这个特殊值要求每一列都有,所以我把它安排在主对角线上,代码如下



import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner scanner=new Scanner(System.in);
		int n=scanner.nextInt();
		int k=scanner.nextInt();
		int a[][]=new int[n][n];
		for (int i = 0; i < a.length; i++) {
			for (int j = 0; j < a.length; j++) {
				if(j==i) {
					a[i][j]=k-k/n*(n-1);
				}else {
					a[i][j]=k/n;
				}
				System.out.print(a[i][j]+" ");
				
			}
			System.out.println();
		}

	}

}