select u.device_id, university, count(question_id) as question_cnt, sum( case when result = 'right' then 1 else 0 end ) as right_question_cnt from user_profile u left join question_practice_detail p on u.device_id = p.device_id and date between '2021-08-01' and '2021-08-31' where university = '复旦大学' group by u.device_id;