稍微优化了一下第一个代码,用‘1’表示访问过
class Solution {
public:
bool exist(vector<vector<char> > &board, string word) {
int m = board.size();
int n = board[0].size();
for (int i = 0; i < m; i++)
{
for (int j = 0; j < n; j++)
{
if (dfs(board, word, 0, i, j)) return true;
}
}
return false;
}
bool dfs(vector<vector<char> > &board, string& word, int pos, int x, int y)
{
if (pos == word.size()) return true;
if (x < 0 || x >= board.size() || y <0 || y >= board[0].size()) return false;
if (board[x][y] != word[pos]) return false;
char t = board[x][y];
board[x][y] = '1';
bool a = dfs(board, word, pos + 1, x + 1, y) ||
dfs(board, word, pos + 1, x - 1, y) ||
dfs(board, word, pos + 1, x, y + 1) ||
dfs(board, word, pos + 1, x, y - 1);
board[x][y] = t;
return a;
}
};


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