#include<bits/stdc++.h>
using namespace std;
int main(){
    float a,b,c;
    cin>>a>>b>>c;
    const double eps=1e-7;
    if(abs(a-b-c)<eps){
        cout<<"YES"<<endl;
    }else{
        cout<<"NO"<<endl;
    }
   //cout<<a-b-c;
}

定义一个小量使精度问题解决