题解 | #字符串加解密#

#include <cctype>
#include <iostream>
using namespace std;

char srcstr[] = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
char encstr[] = "BCDEFGHIJKLMNOPQRSTUVWXYZAbcdefghijklmnopqrstuvwxyza1234567890";
char decstr[] = "ZABCDEFGHIJKLMNOPQRSTUVWXYzabcdefghijklmnopqrstuvwxy9012345678";

void encrypt2(string& str) {
    int len = str.length();
    for (int i = 0; i < len; i++) {
        if (isupper(str[i])) {
            str[i] = encstr[str[i] - 'A' + 26];
        } else if (islower(str[i])) {
            str[i] = encstr[str[i] - 'a'];
        } else {
            str[i] = encstr[str[i] - '0' + 52];
        }
    }
    return;
}

void decrypt2(string& str) {
    int len = str.length();
    for (int i = 0; i < len; i++) {
        if (isupper(str[i])) {
            str[i] = decstr[str[i] - 'A' + 26];
        } else if (islower(str[i])) {
            str[i] = decstr[str[i] - 'a'];
        } else {
            str[i] = decstr[str[i] - '0' + 52];
        }
    }
    return;
}



int main() {
    string encryptStr;  // 要加密的字符串
    string decryptStr;  // 要解密的字符串
    cin >> encryptStr;
    cin >> decryptStr;

    // 加密函数
    encrypt2(encryptStr);

    // 解密函数
    decrypt2(decryptStr);

    cout << encryptStr << endl;
    cout << decryptStr << endl;
    return 0;
}
// 64 位输出请用 printf("%lld")