题解 | #计算日期到天数转换#

/*
 * @Description: If you get question about the code, contact me at **********.
 * @Author: pengjunxing
 * @Date: 2023-02-10 20:32:13
 * @LastEditors: pengjunxing
 * @LastEditTime: 2023-02-10 20:49:15
 */
#include<iostream>
using namespace std;
int main()
{
    int year,month,day,num;
    num=0;
    cin>>year>>month>>day;
    int m[12]={31,28,31,30,31,30,31,31,30,31,30,32};
    if(year%4==0)
    {
        m[1]=29;
    }
    if(year%100==0&&year%400!=0)
    {
        m[1]=28;
    }
    for(int i=0;i<month-1;i++)
    {
        num+=m[i];
    }
    cout<<num+day;
}