题目

对给定的一个字符串,找出有重复的字符,并给出其位置,如:abcaaAB12ab12 输出:a,1;a,4;a,5;a,10,b,2;b,11,1,8;1,12, 2,9;2,13。

//使用map + vector的方法吧
#include <iostream>
#include <map>
#include <string>
#include <vector>
#include <algorithm>
using namespace std;
int main() {
    string str;
    while(cin>>str) {
        map<char, vector<int>> mp;
        vector<char> v;
        for(int i = 0; i < str.size(); i++) {
            if (mp.find(str[i]) != mp.end()) { //existed
                mp[str[i]].push_back(i);
            } else {
                vector<int> add;
                add.push_back(i);
                mp[str[i]] = add;
                v.push_back(str[i]);
            }
        }
//         sort(v.begin(), v.end());
        for (int i = 0; i < v.size(); i++) {
            if (mp[v[i]].size() > 1) {
                for (int j = 0; j < mp[v[i]].size() - 1; j++) {
                    cout<<v[i]<<":"<<mp[v[i]][j]<<",";
                }
                cout<<v[i]<<":"<<mp[v[i]][mp[v[i]].size() - 1];
                cout<<endl;
            }

        }
    }
    return 0;
}