题解 | #炮台攻击# C++

#include <iostream>
#include <cmath>
#include <vector>
using namespace std;

int main() {
    int R;  //炮台攻击半径
    while(cin >> R){
        vector<vector<int>> tanks;
        vector<int> tank(2);
        for(int i=0; i<3; i++){    //存入三个炮台的坐标
            cin >> tank[0] >> tank[1];
            tanks.push_back(tank);
        }
        vector<int> enemy(2);
        cin >> enemy[0] >> enemy[1];  //存入敌人坐标
        int damage = 0;
        for(vector<int> temp : tanks){  //遍历每个炮台
            int x1 = temp[0], y1 = temp[1];
            int x2 = enemy[0], y2 = enemy[1];
            double len = sqrt((x1-x2)*(x1-x2) + (y1-y2)*(y1-y2));
            if(len <= R)
                damage++;
        }
        cout << damage << 'x' << endl;
    }
    return 0;
}
// 64 位输出请用 printf("%lld")