题解 | 奇偶统计

#include <stdio.h>

int main() {
    int N;
    int odd = 0;
    int even = 0;
    scanf("%d",&N);
    for(int m =1;m<=N;m++)
    {
        if(m%2==0)even++;
        if(m%2!=0)odd++;
    }     
    printf("%d %d",odd,even);
    return 0;
}