题解 | 翻转金字塔图案

#include <stdio.h>

int main()
{
	int n = 0; 
	while (scanf("%d", &n) != EOF)
	{
		for (int i = 0; i < n; i++)
		{
			for (int k = 0; k < i; k++)
			{
				printf(" ");
			}
			for (int j = 0; j < n - i; j++)
			{
				printf("* ");
			}
			printf("\n");
		}
	}
	return 0;
}