题解 | 计算日期到天数转换

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#include <iostream>
#include <vector>
using namespace std;

int main() {
    int year, month, day;
    cin >> year >> month >> day;
    vector<int> days = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    bool is_leap_year = (year%4 == 0 && year%100) || year%400 == 0;
    if(is_leap_year) days[1] = 29;
    int ans = 0;
    for(int i = 0; i < month - 1; ++i) {
        ans += days[i];
    }
    ans += day;
    cout << ans << endl;
    return 0;
}