字符串解法:
#include <iostream>
using namespace std;
int main() {
int n, x;
std::cin >> n >> x;
std::string s;
int count = 0;
for (int i = 1; i <= n; ++i) {
s = std::to_string(i);
for (char c : s) {
if (c == '0' + x) {
++count;
}
}
}
std::cout << count << std::endl;
}
// 64 位输出请用 printf("%lld")

京公网安备 11010502036488号