#思路:输入num,从num/2 向前遍历,满足条件的j,num-j 为:当j和num-j都为素数时满足条件
def is_SS(num):为:
i = 2
while i ** 2 <= num:
if num % i == 0:
return False
i += 1
return True
while True:
try:
a = int(input())
j = a // 2
while j > 0:
if is_SS(j) and is_SS(a - j):
print(j)
print(a-j)
break
j -= 1
except:
break