题解 | #计算一元二次方程#

#include <math.h>
int main() {
    float a, b, c;
    while (scanf("%f %f %f", &a, &b, &c) != EOF) {
        if (a == 0) {
            printf("Not quadratic equation\n");
        } else {
            float deta = b * b - 4 * a * c;
            if (deta >= 0) {
                float result1 = (-b + sqrt(deta)) / (2 * a);
                float result2 = (-b - sqrt(deta)) / (2 * a);
                if (deta > 0) {
                    printf("x1=%.2f;x2=%.2f\n", result2, result1);
                } else {

                    if (result1 == 0) {
                        printf("x1=x2=0.00\n");
                    } else {
                        printf("x1=x2=%.2f\n", result1);
                    }
                }

            
        } else {
            float shibu = (-b) / (2.0 * a);
            float xubu = (sqrt(-deta)) / (2.0 * a);
            if (xubu < 0) {
                xubu = -xubu;
                printf("x1=%.2f-%.2fi;x2=%.2f+%.2fi\n", shibu, xubu, shibu, xubu);
            } else {
                printf("x1=%.2f-%.2fi;x2=%.2f+%.2fi\n", shibu, xubu, shibu, xubu);
            }
        }
    }
}
return 0;

}