题意 : 求凸包周长
思路:处理出凸包,两点距离公式
#include<cstdio>
#include<vector>
#include<cmath>
#include<string>
#include<string.h>
#include<iostream>
#include<algorithm>
#define PI acos(-1.0)
#define pb push_back
#define F first
#define S second
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
const int N=3e5+5;
const int MOD=1e9+7;
template <class T>
bool sf(T &ret){ //Faster Input
char c; int sgn; T bit=0.1;
if(c=getchar(),c==EOF) return 0;
while(c!='-'&&c!='.'&&(c<'0'||c>'9')) c=getchar();
sgn=(c=='-')?-1:1;
ret=(c=='-')?0:(c-'0');
while(c=getchar(),c>='0'&&c<='9') ret=ret*10+(c-'0');
if(c==' '||c=='\n'){ ret*=sgn; return 1; }
while(c=getchar(),c>='0'&&c<='9') ret+=(c-'0')*bit,bit/=10;
ret*=sgn;
return 1;
}
int sign(double x){
return abs(x)<1e-7?0:x<0?-1:1;
}
struct Point{
double x,y;
Point(double x=0.0, double y=0.0) : x(x), y(y) {}
Point operator - (const Point &rhs) const{
return Point(x-rhs.x,y-rhs.y);
}
bool operator == (const Point &rhs) const{
return sign(x-rhs.x)==0&&sign(y-rhs.y)==0;
}
bool operator < (const Point &rhs)const{
if(x==rhs.x) return y<rhs.y;
else return x<rhs.x;
}
};
typedef Point Vector;
double cross(Vector A,Vector B){
return A.x*B.y-A.y*B.x;
}
int n;
typedef vector<Point> Polygon;
Polygon convex_hull(Polygon P){
sort(P.begin(),P.end());
P.erase(unique(P.begin(), P.end()), P.end());
int n=P.size(),k=0;
Polygon Q(n*2);
for(int i=0;i<n;++i){
while(k>1&&cross(Q[k-2]-Q[k-1],Q[k-2]-P[i])<=0) k--;
Q[k++]=P[i];
}
int t=k;
for(int i=n-2;i>=0;--i){
while(k>t && cross(Q[k-2]-Q[k-1],Q[k-2]-P[i])<=0) k--;
Q[k++]=P[i];
}
Q.resize(k);
return Q;
}
double dis(Point a,Point b){
return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));
}
int main(void){
int r;
while(cin>>n>>r){
Polygon t;
for(int i=1;i<=n;i++){
double x,y;
scanf("%lf%lf",&x,&y);
t.push_back({x,y});
}
vector<Point> ans=convex_hull(t);
double res=0.0;
// cout <<"---------"<<endl;
// for(auto t : ans) cout << t.x <<" "<<t.y<<endl;
// ans.pb(ans[0]);
for(int i=0;i<(int)ans.size()-1;++i) res+=dis(ans[i],ans[i+1]);
// printf("area=%f\n",res);
if(res<0) res=-res;
res+= 2.0*PI*r;
// printf("area=%f\n",res);
printf("%d\n",(int)(res+0.5));
}
return 0;
}