with question_practice_detail as (
select distinct device_id,date
from question_practice_detail
)
select round(count(y.date)/count(x.date),4) as avg_ret
from question_practice_detail x
left join question_practice_detail y
on x.device_id=y.device_id and datediff(y.date,x.date)=1

京公网安备 11010502036488号