题解 | #xxx定律#

#include<stdio.h>
int f(int n) {
    if (n == 1)return 0;
    else if (n % 2 == 0)return 1 + f(n / 2);
    return 1 + f((3 * n + 1) / 2);
}
int main() {
    int n;
    while (scanf("%d", &n) != EOF) {
        printf("%d", f(n));
    }
    return 0;
}