不用group by having
select
  distinct uid,
  exam_complete_cnt
from
  (
    select
      uid,
      sum(if(submit_time is null, 1, 0)) over w AS uncomplete_cnt,
      count(submit_time) over w AS exam_complete_cnt
    from
      (
        select
          uid,
          submit_time,
          DENSE_RANK() over(
            PARTITION BY uid
            order by
              date_format(start_time, '%Y%m') desc
          ) recent_m
        from
          exam_record
      ) t1
    where
      recent_m < 4 window w AS (PARTITION BY uid)
  ) tmp
where
  uncomplete_cnt = 0
order by
  exam_complete_cnt desc,
  uid desc;