题解 | #得分不小于平均分的最低分#

select
	score as min_score_over_avg
from exam_record e
join examination_info 
	using (exam_id)
where tag = 'SQL' 
	and score >= (
		select
			avg(score)
		from exam_record
		join examination_info 
			using (exam_id)
		group by tag
		having tag = 'SQL'
    )
order by score
limit 1