A. Doggo Recoloring

Panic is rising in the committee for doggo standardization — the puppies of the new brood have been born multi-colored! In total there are 26 possible colors of puppies in the nature and they are denoted by letters from 'a' to 'z' inclusive.

The committee rules strictly prohibit even the smallest diversity between doggos and hence all the puppies should be of the same color. Thus Slava, the committee employee, has been assigned the task to recolor some puppies into other colors in order to eliminate the difference and make all the puppies have one common color.

Unfortunately, due to bureaucratic reasons and restricted budget, there's only one operation Slava can perform: he can choose a color xx such that there are currently at least two puppies of color xx and recolor all puppies of the color xxinto some arbitrary color yy. Luckily, this operation can be applied multiple times (including zero).

For example, if the number of puppies is 77 and their colors are represented as the string "abababc", then in one operation Slava can get the results "zbzbzbc", "bbbbbbc", "aaaaaac", "acacacc" and others. However, if the current color sequence is "abababc", then he can't choose xx='c' right now, because currently only one puppy has the color 'c'.

Help Slava and the committee determine whether it is possible to standardize all the puppies, i.e. after Slava's operations all the puppies should have the same color.

Input

The first line contains a single integer nn (1≤n≤1051≤n≤105) — the number of puppies.

The second line contains a string ss of length nn consisting of lowercase Latin letters, where the ii-th symbol denotes the ii-th puppy's color.

Output

If it's possible to recolor all puppies into one color, print "Yes".

Otherwise print "No".

Output the answer without quotation signs.

Examples

input

6
aabddc

output

Yes

input

3
abc

output

No

input

3
jjj

output

Yes

水题，判断有没有元素的数量大于等于2即可，可以用set写。

代码：

#include<iostream>
#include<algorithm>
#include<cstring>
#include<string>
#include<cstdio>
#include<cmath>
#include<set>
using namespace std;
#define inf 0x3f3f3f3f
#define ll long long
#define closeio std::ios::sync_with_stdio(false)
#define mem(a,b) memset(a,b,sizeof(a))

int main()
{
	int n,i;
	string a;
	set<char>q;
	cin>>n;
	cin>>a;
	for(i=0;i<n;i++)
		q.insert(a[i]);
	//cout<<q.size()<<endl;
	if(q.size()==n&&n!=1)    //当n==1时只有一个元素，不能被染色
		cout<<"No"<<endl;
	else
		cout<<"Yes"<<endl;
	return 0;
}