//由于数组有序,所以使用二分查找方法定位k的第一次出现位置和最后一次出现位置
class Solution {
public:
int GetNumberOfK(vector<int> data ,int k) {
int lower = getLower(data,k);
int upper = getUpper(data,k);
return upper - lower + 1;
}
//获取k第一次出现的下标
int getLower(vector<int> data,int k){
int start = 0,end = data.size()-1;
int mid = (start + end)/2;
while(start <= end){
if(data[mid] < k){
start = mid + 1;
}else{
end = mid - 1;
}
mid = (start + end)/2;
}
return start;
}
//获取k最后一次出现的下标
int getUpper(vector<int> data,int k){
int start = 0,end = data.size()-1;
int mid = (start + end)/2;
while(start <= end){
if(data[mid] <= k){
start = mid + 1;
}else{
end = mid - 1;
}
mid = (start + end)/2;
}
return end;
}
};