题解 | #确定最佳顾客的另一种方式（二）#

-- 三表连结inner join写法
select
    cust_name,
    sum(item_price * quantity) total_price
from
    OrderItems
    inner join Orders on OrderItems.order_num = Orders.order_num
    inner join Customers on Customers.cust_id = Orders.cust_id
group by
    cust_name
having
    total_price >= 1000
order by
    total_price