题解 | 简单计算器

#include <iostream>
using namespace std;

int main() {
    double a, b;
    char oper;
    scanf("%lf%c %lf",&a,&oper,&b);
    double solu;
    if (oper == '+')
    {
        solu = a + b;
        printf("%.4f+%.4f=%.4f",a,b,solu);
    }
    else if (oper == '-')
    {
        solu = a -b;
        printf("%.4f-%.4f=%.4f",a,b,solu);
    }
    else if (oper == '*')
    {
        solu = a*b;
        printf("%.4f*%.4f=%.4f",a,b,solu);
    }
    else if (oper == '/')
    {
        if (b == 0)
        {
            printf("Wrong!Division by zero!");
        }
        else
        {
            solu = a/b;
            printf("%.4f/%.4f=%.4f",a,b,solu);
        }
    }
    else
    {
        printf("Invalid operation!");
    }
    return 0;
} 
// 64 位输出请用 printf("%lld")