题解 | #简单密码#

# #解法1，直接if else
# import sys
# def convert(c):
#     if c.isupper():
#         if c == 'Z':
#             return "a"
#         else:
#             return chr(ord(c.lower()) + 1)
#     elif c in "abc":
#         return '2'
#     elif c in "def":
#         return '3'
#     elif c in "ghi":
#         return '4'
#     elif c in "jkl":
#         return '5'
#     elif c in "mno":
#         return '6'
#     elif c in "pqrs":
#         return '7'
#     elif c in "tuv":
#         return '8'
#     elif c in "wxyz":
#         return '9'
#     else:
#         return c

# while True:
#     try:
#         p = input()
#         result = ""
#         for i in range(len(p)):
#             result += convert(p[i])
#         print(result)

#     except:
#         #print(sys.exc_info())
#         break



#解法2，搞一个字典
dic = {"abc":'2', "def":'3', "ghi":'4',"jkl":'5',"mno":"6","pqrs":'7',"tuv":'8',"wxyz":'9'}
def convert(c):
    if c.isupper():
        if c == 'Z':
            return "a"
        else:
            return chr(ord(c.lower()) + 1)
    if c.islower():
        for key in dic:
            if c in key:
                return dic[key]
    else:
        return c

while True:
    try:
        p = input()
        result = ""
        for i in range(len(p)):
            result += convert(p[i])
        print(result)

    except:
        #print(sys.exc_info())
        break