题解 | 小苯的刷怪笼

#include <iostream>
using namespace std;

int main() {
    long n, a, k;
    cin >> n >> a >> k;
    if (a < n)
    {
        cout << "-1";
        return 0;
    }
    else
    {
        if (a > 2 * k || a < k)
        {
            cout << "-1";
            return 0;
        }
        else
        {
            if (n == 1)
            {
                if (a != k)
                {
                    cout << "-1";
                    return 0;
                }
                else
                {
                    cout << k;
                    return 0;
                }
            }
            else
            {
                //cout << "k=" << k << " a=" << a << "\n";
                k -= (n - 2 + 1) / 2;
                a -= (n - 2);
                //cout << "k=" << k << " a=" << a << "\n";
                int t1 = k;
                int t2 = a - t1;
                cout << t1 << " " << t2;
                for (int i = 1; i <= n - 2; i++)
                {
                    cout << " " << 1;
                }
            }
        }
    }
    return 0;
}
// 64 位输出请用 printf("%lld")